Topics/Questions discussed in this video:
NCERT Miscellaneous Exercise Class 12 Maths Chapter 2 Inverse Trigonometric Functions
Question-1. \cos^{-1}\cos\frac{13\pi}{6}
Question-2. \tan^{-1}\tan\frac{7\pi}{6}
Question-3. 2 \sin^{-1}\frac{3}{5}= \tan^{-1}\frac{24}{7}
Question-4. \sin^{-1}\frac{8}{17}+\sin^{-1}\frac{3}{5}=\tan^{-1}\frac{77}{36}
Question-5. \cos^{-1}\frac{4}{5}+\cos^{-1}\frac{12}{13}=\cos^{-1}\frac{33}{65}
Question-6. \cos^{-1}\frac{12}{13}+\sin^{-1}\frac{3}{5}=\sin^{-1}\frac{56}{65}
Question-7. \tan^{-1}\frac{63}{16}=\sin^{-1}\frac{5}{13}+\cos^{-1}\frac{3}{5}
Question-8. \tan^{-1}\frac{1}{5}+\tan^{-1}\frac{1}{7}+\tan^{-1}\frac{1}{3}+\tan^{-1}\frac{1}{8}=\frac{\pi}{4}
Question-9. \tan^{-1}\sqrt{x}=\frac{1}{2} \cos^{-1}\frac{1-x}{1+x},x \in 0,1
Question-10. cot^{-1}\left ( \frac{\sqrt{1+\sin x }+\sqrt{1-\sinx }}{\sqrt{1+\sin x }-\sqrt{1-\sinx}} \right )=\frac{x}{2}
Question-11. \tan^{-1}\frac{\sqrt{1+x}-\sqrt{1-x}}{\sqrt{1+x}+\sqrt{1-x}}=\frac{\pi}{4}-\frac{1}{2} \cos^{-1}x
Question-12. \frac{9\pi}{8}-\frac{9}{4} \sin^{-1}\frac{1}{3}=\frac{9}{4} \sin^{-1}\frac{2\sqrt{2}}{3}
Question-13. 2 \tan^{-1}{ \cosx}=\tan^{-1}{ 2\cosec x}
Question-14. \tan^{-1}\frac{1-x}{1+x}=\frac{1}{2} \tan^{-1}x,
Question-15. \sin(\tan^{-1}x),
Question-16. \sin^{-1}(1-x)-2 \sin^{-1}x=\frac{\pi}{2}
Question-17. \tan^{-1}\frac{x}{y} -\tan^{-1}\frac{x-y}{x+y}
Full chapter is now available to buy...
Ch2. Inverse Trigonometric Functions
In this self study course, you will learn definition, range, domain, principal value branch, graphs of inverse trigonometric functions and elementary properties of inverse trigonometric functions. For further understanding of concepts and for examination preparation, practice questions based on the above topics are discussed in the form of assignments that has questions from NCERT Textbook exercise, NCERT Examples, Board’s Question Bank, RD Sharma, NCERT Exemplar etc. instead of only one book. The PDF of assignments can be downloaded within the course.
₹850.00 ₹650.00