NCERT Exercise 2.2 Question 9 Inverse Trigonometric Functions

Chapter 2 Inverse Trigonometric Functions Class 12 Maths

NCERT Exercise 2.2 Question 9 Inverse Trigonometric Functions { \displaystyle {\tan }^{-1} \left ( \frac{x}{\sqrt{a^2-x^2}} \right ), | x | < a}

simplify-sin-inverse-5-over-13-cos-x-plus-12-over-13-sin-x-rd-sharma-question 06:15

Simplify sin inverse 5 over 13 cos x plus 12 over 13 sin x RD Sharma Question

Updated

:

November 1, 2022, 5:14 am

Simplify: {\displaystyle \sin ^{-1} \left ( \frac{5}{13} \cos x+\frac{12}{13} \sin x \right ) }