NCERT Exercise 2.2 Question 9 Inverse Trigonometric Functions
Chapter 2 Inverse Trigonometric Functions Class 12 Maths
NCERT Exercise 2.2 Question 9 Inverse Trigonometric Functions { \displaystyle {\tan }^{-1} \left ( \frac{x}{\sqrt{a^2-x^2}} \right ), | x | < a}
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Simplify sin inverse 5 over 13 cos x plus 12 over 13 sin x RD Sharma Question
Updated
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November 1, 2022, 5:14 am
Simplify: {\displaystyle \sin ^{-1} \left ( \frac{5}{13} \cos x+\frac{12}{13} \sin x \right ) }