# NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions Example 1

## Chapter 3 Trigonometric Functions Class 11 Maths

NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions Example 1 A circular wire of radius 3 cm is cut and bent so as to lie along the circumference of a hoop whose radius is 48 cm. Find the angle in degrees which is subtended at the centre of hoop.

## NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions Example 4

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November 1, 2022, 5:14 am

NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions Example 4 If θ lies in the second quadrant, then show that { \displaystyle \sqrt{\frac{1-\sin\theta}{1+\sin\theta}} + \sqrt{\frac{1+\sin\theta}{1-\sin\theta}} = -2 \sec\theta }

## NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions Example 3

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November 1, 2022, 5:14 am

NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions Example 3 Find the value of { \displaystyle \sqrt{3} \text{cosec} 20^\circ – \sec 20^\circ }

## NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions Example 2

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November 1, 2022, 5:14 am

NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions Example 2 If { \displaystyle A = cos^2 θ + sin^4 θ } for all values of θ, then prove that { \displaystyle \frac{3}{4} \le A \le 1} .

## Prove that (sec8θ−1)/(sec4θ−1)=tan8θ/tan2θ

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November 1, 2022, 5:14 am

NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions **Example 6:** Prove that { \displaystyle \frac{sec8\theta-1}{sec4\theta-1}=\frac{tan8\theta}{tan2\theta}}

## Find the value of tan9°–tan27°–tan63°+tan81°

### Updated

November 1, 2022, 5:14 am

NCERT Exemplar Class 11 Maths Chapter 3 Trigonometry Functions Example 5: Find the value of tan9°–tan27°–tan63°+tan81°